(5(x^4))+(40(x^2))-100=0

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Solution for (5(x^4))+(40(x^2))-100=0 equation:


Simplifying
(5(x4)) + (40(x2)) + -100 = 0

Reorder the terms:
-100 + (40x2) + (5x4) = 0

Solving
-100 + (40x2) + (5x4) = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '5'.
5(-20 + (8x2) + x4) = 0

Factor a trinomial.
5((-10 + -1x2)(2 + -1x2)) = 0

Ignore the factor 5.

Subproblem 1

Set the factor '(-10 + -1x2)' equal to zero and attempt to solve: Simplifying -10 + -1x2 = 0 Solving -10 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1x2 = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1x2 = 0 + 10 -1x2 = 0 + 10 Combine like terms: 0 + 10 = 10 -1x2 = 10 Divide each side by '-1'. x2 = -10 Simplifying x2 = -10 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + -1x2)' equal to zero and attempt to solve: Simplifying 2 + -1x2 = 0 Solving 2 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x2 = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x2 = 0 + -2 -1x2 = 0 + -2 Combine like terms: 0 + -2 = -2 -1x2 = -2 Divide each side by '-1'. x2 = 2 Simplifying x2 = 2 Take the square root of each side: x = {-1.414213562, 1.414213562}

Solution

x = {-1.414213562, 1.414213562}

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